(4x-1)^2=20x-5

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Solution for (4x-1)^2=20x-5 equation: 



(4x-1)^2=20x-5

We move all terms to the left:

(4x-1)^2-(20x-5)=0

We get rid of parentheses

(4x-1)^2-20x+5=0

We add all the numbers together, and all the variables

-20x+(4x-1)^2+5=0

We move all terms containing x to the left, all other terms to the right

-20x+(4x-1)^2=-5

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